integration of 1 cos2x/2 from pi to 0 (these are limits) is equal to (a) pi/4 (b) pi/2 (c) pi/3 (d) pi
![Integrate :- (Cos x - Cos 2x)/(1-Cos x) dx cos x — cos 2x 20 f dx I — - Maths - Integrals - 12979127 | Meritnation.com Integrate :- (Cos x - Cos 2x)/(1-Cos x) dx cos x — cos 2x 20 f dx I — - Maths - Integrals - 12979127 | Meritnation.com](https://s3mn.mnimgs.com/img/shared/content_ck_images/ck_d45ccb116d0a1633aa4ae4144a15c581.png)
Integrate :- (Cos x - Cos 2x)/(1-Cos x) dx cos x — cos 2x 20 f dx I — - Maths - Integrals - 12979127 | Meritnation.com
![SOLVED: Formulas: 1. 13 sin x + cos x = 1 - cos(2x) - 2sin x = 2 - 1 + cos( 2x) - 3cos x = 2. 2. 4 sin(2x) = 2sin SOLVED: Formulas: 1. 13 sin x + cos x = 1 - cos(2x) - 2sin x = 2 - 1 + cos( 2x) - 3cos x = 2. 2. 4 sin(2x) = 2sin](https://cdn.numerade.com/ask_images/d2a67a0e4d744dd9946744b15d272db2.jpg)
SOLVED: Formulas: 1. 13 sin x + cos x = 1 - cos(2x) - 2sin x = 2 - 1 + cos( 2x) - 3cos x = 2. 2. 4 sin(2x) = 2sin
![algebra precalculus - How does $\frac{\cos x}{1-\cos^2x}=\frac23$ become $\ cos x=\frac12$? - Mathematics Stack Exchange algebra precalculus - How does $\frac{\cos x}{1-\cos^2x}=\frac23$ become $\ cos x=\frac12$? - Mathematics Stack Exchange](https://i.stack.imgur.com/VTE2h.png)